How do you find the restrictions of #3/(x-4)-7#?

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Answer 1 · 2017-09-28T14:09:16

#x!= 4#

if #x=4#, you will have #3/0 -7# which is undefined.
So, we exclude that from the domain of x.

Answer 2 · 2017-09-28T14:09:19

See a solution process below:

We cannot divide by #0#.

Therefore:

#x - 4 != 0#

Or

#x - 4 + color(red)(4) != 0 + color(red)(4)#

#x - 0 != 4#

#x != 4#