How do you solve #12= - r - 5r#?

3 Answers
Sep 29, 2017

#r=-2#

Explanation:

First we begin by simplifying the right side. Notice how #-r# and #-5r# are actually like terms with #-r# having a #-1# as a coefficient. And so, we can combine these two terms:

#12=-color(blue)1r-5r#

#12=-6r#

Now we can solve for #r# by dividing both sides by #-6#

#12/color(red)(-6)=cancel(-6)/cancelcolor(red)(-6)r#

#-2=r#

Sep 29, 2017

#r=-2#

Explanation:

#12 = -r-5r#
#12 = -6r#
Flip the equation
#-6r = 12#
Divide both sides by #-6#
#(-6r)/(-6)=12/(-6)#
#r = -2#

Sep 29, 2017

#r=-2#

Explanation:

#(-r-5r)=12#
#-(r+5r)=12#
#(r+5r)=-12#
#6r=-12#
#r=-12/6#
#r=-2#