How do you simplify #(c^4d^4f^3)/(c^2d^4f^3)#?

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Answer 1 · 2017-09-29T22:49:50

The answer is #c^2#.

The first thing to take note is that you have several variables (namely, #c#, #d#. and #f#). Using the exponential law

#(a^n)/(a^m) = a^(n-m)#

we have

#[c^(4-2)][d^(4-4)][f^(3-3)]#

Further applying the law

#a^0 = 1#

the variables #f# and #d# are equivalent to #1#. As such, you are left with

#c^2 * 1 * 1#

which is equal to #c^2#.