Question

Question #4eb4a

Answer 1

See the answer below...
Think it to be `E/2`
Hope it helps...

Explanation:

Suppose,the spring `A` and `B` stretches by the length `x_1` and `x_2` unit.
We know that Increase in length is directly proportional to force applied but negative in sign.
So we can write,
`F=-kx_1` and `F=-2kx_2` [because each time force used is equal]
From the equation we can write that `-kx_1=-2kx_2=>x_1=2x_2`
Here,we also know for the spring `A` ,
`E=1/2kx_1^2`
So for the spring `B` the energy restored will be `1/2xx2kxxx_2^2=>1/2xx2kxxx_1^2/4=E/2`