Question

Calculate the acceleration of a 2000-kg, single-engine airplane as it begins its takeoff with an engine thrust of 500 N ?

Steps please .. thank you^^

Answer 1

`0.25 ms^-2`

Explanation:

It's very simple according to newton's second law of motion acceleration of a particle is equal to the ratio of force applied to the mass of the body.

`a=F/m`

The force applied here is the thrust .

After substituting the values

`a=500/2000 ms^-2`
`a=1/4 ms^-2`

`a=0.25 ms^-2`

Answer 2

0.25 m/s²

Explanation:

a = `F / m`

= `(500 N) / (2000 kg)`

= 0.25 m/s²