What are the intercepts of #2x-13y=-17#?

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Answer 1 · 2017-09-30T16:07:01

#(0,17/13)# and #(-17/2,0)#

A y-axis intercept occurs on the axis when the x value is equal to 0. The same with the x-axis and the y value being equal to 0

So if we let x=0, we will be able to solve for the y value at the intercept.

#2(0)-13y=-17#
#-13y=-17#
#y=(-17)/(-13)#
#y=17/13#

So the y-axis intercept occurs when x=0 and y=17/13 giving the co-ordinate.

#(0,17/13)#

To find the x-axis intercept we do the same thing but let y=0.

#2x-13(0)=-17#
#2x=-17#
#x=-17/2#

The x-axis intercept occurs when y=0 and x=-17/2 giving the co-cordinate

#(-17/2,0)#