Question

How do you solve `-b + \frac { 8} { 5} b = 9?`

Answer 1

Given: `-b + 8/5b = 9`

Combine like terms:

`3/5b = 9`

Multiply both sides of the equation by `5/3`:

`b = (5/3) 9`

`b = 15`

Check:

`-(15) + 8/5(15) = 9`

`-15 + 8(3) = 9`

`-15+24=9`

`9 = 9`

This checks.

Answer 2

`-b+(8b)/5=9`
`-5b+8b=45`
I transferred 5 from LHS to RHS, and when we do that or vice versa, we inverse it, i.e. if addition then subtraction(and vice versa), if multiplication then division(and vice versa).

Also note that when doing -5b+8b, it seems a little complex, do it is also equal to 8b-5b, which seems a lot simpler.
`3b=45`
`b=45/3`
`b=15`