How do you evaluate #(2z-15x)/(3y)# if w=6, x=0.4, y=1/2, z=-3?
1 Answer
Sep 30, 2017
Explanation:
#"substitute given values into the expression"#
#rArr(2z-15x)/(3y)#
#=((2xx-3)-(15xx0.4))/(3xx1/2)#
#=(-6-6)/(3/2)#
#=-12xx2/3#
#=-8#
