Question

Question #99fa3

Answer 1

`15.7g`

Explanation:

With the reaction balanced, the mass balance (conservation of mass) means that the reactants must also total 56.4g. So first, let’s convert the molar ratio into a mass ratio.
`C_4H_(10)O = 74g` `6O_2 = 192g`

The total normalized mass is 266g. We have only 56.4g, so we only have `56.4/266 = 0.212` of a “unit”.
Applying that to the molar ratios, we obtain
`0.212 xx ( C_4H_(10)O + 6O_2) = 0.212` moles `C_4H_(10)O` and `1.27` moles of `O_2`.

`74g/(mol) C_4H_(10)O xx 0.212 = 15.7g`
`32g/(mol) O_2 xx 1.27 = 40.7g`
CHECK: `15.7 + 40.7 = 56.4` CORRECT!