How do you solve the equation #x^2-324=0#?

Question

7480 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-01T03:46:49

Given: #x^2-324=0#

Add 324 to both sides:

#x^2=324#

Use the square root on both sides:

#x=+-18#

This means that the solutions are #x = 18 and x = -18#

Answer 2 · 2017-10-01T03:54:22

#x=18#

#x^2-324=0#
#x^2=324=18*18=18^2#
#:.x=18#

Answer 3 · 2017-10-01T09:18:41

#x = 18 or x=-18#

This can be solved by factorising the quadratic using the difference of two squares.

#x^2-324 =0#

#(x+18)(x-18)=0#

Set each factor equal to #0#

#x+18=0 " "rarr x = -18#

#x-18=0" "rarr x =18#