Question #4c1b0
1 Answer
Oct 1, 2017
Explanation:
#"expand "f(x)=(x+3)^2-1#
#rArrf(x)=x^2+6x+9-1=x^2+6x+8#
#"the factors of + 8 which sum to + 6 are + 2 and + 4"#
#rArrx^2+6x+8=(x+2)(x+4)#
#f(x)=(x+3)^2-1=(x+2)(x+4)color(blue)" in intercept form"#
