Question

Question #9be26

Answer 1

`0.42"m"`

Explanation:

`"specific gravity of wood" ->(700"kgm"/m^3)/(1000"kgm"/m^3) = 0.7 ("no units!")`

`% "of wood immersed" = 0.7*100 = 70%`

`"volume of cube" = (0.6m)^3 = 0.216m^3`

`"depth of wood immersed" = 70%*0.215 = 0.1512m^3`

Two of its sides will remain the same while immersed. So the depth`(d)` immersed,

`0.6*0.6*d = 0.1512`

`=>d=(0.1512m^3)/(0.6m*0.6m)=0.42m`