Question

Question #5efb7

Answer 1

The value of `x` comes to be 3.

Explanation:

Given that,
`log(x+2)-log(3x-4)=0`
`:.log(x+2)=log(3x-4)`

Now, taking antilog in both sides,

`x+2=3x-4`
`:.color(red)(x=3)`. (Answer).

Hope it Helps :)

Answer 2

`x=3`

Explanation:

Assuming base `10` logarithms

`log(x+2) - log(3x-4)=0 => log(x+2)=log(3x-4)`

Raise `10` to the power of each side.

This is the antilogarithm, such that:

`10^log(a) = a`

So:

`10^log(x+2)= 10^log(3x-4)=> x+2=3x-4=> x=3`