Question

Question #a1a19

Answer 1

Depending on what your teacher is looking for, you might be overthinking this one.

Explanation:

Immediate after heating the copper sulfate forms a dry, light blue solid.

Right after the heating is complete the reaction is:

`CuSO_4*5H_2O(s) -> CuSO_4(s) + 5H_2O(g)`

The addition of water reverses the removal of water.

`CuSO_4(s) + 5H_2O(l) -> CuSO_4*5H_2O(s)`

If you add exactly 5 parts water for every one part copper sulfate the solid will return to being `CuSO_4*5H_2O(s)`.

Adding any extra water will cause the formation of a copper sulfate solution of`CuSO_4*5H_2O(aq)`.

Hope this helps!