How do you find #f(2a)# for #f(x) = 4 - 3x^2#?
1 Answer
Oct 3, 2017
We have
#f(2a) = 4 - 3(2a)^2 = 4 - 3(4a^2) = 4 - 12a^2#
Hopefully this helps!
We have
#f(2a) = 4 - 3(2a)^2 = 4 - 3(4a^2) = 4 - 12a^2#
Hopefully this helps!