How do you find the quotient of (2y^4-3y^2+1)div(y-1) using long division?

1 Answer
Oct 4, 2017

2y^3+2y^2-y-1

Explanation:

" "" "2y^3+2y^2-y-1
y-1|bar(cancel(2y^4)+0y^3-3y^2+0y+1)|
" "" " cancel(2y^4)-2y^3
" "" "bar(0+cancel(2y^3)-3y^2+0y+1)
" "" " 0+cancel(2y^3)-2y^2
" "" "bar( 0+00 cancel(-1y^2)+0y+1)
" "" " 0+00cancel(-1y^2)+y
" "" "bar( 0+00+00cancel(-1y+1)
" "" " 0+00+00cancel(-1y+1
" "" "bar(................................)

Note:
The sign is changed (+ to - or - to +) when the term is multiplied with the term in the quotient.