How do you solve #6( 2q - 3) = 26- 4( q - 9)#?

1 Answer
Rorochevre
Oct 4, 2017

#q=5#

Explanation:

Use distributivity laws to simplify the equation and then solve it:

  • #6(2q-3) = 26 - 4(q-9) =>#
  • #12q-18 = 26 - 4q+36 => #
  • #12q + 4q = 26 + 36 + 18 =># ||||||| (add #4q+18# to both sides)
  • #16q = 80 =>#
  • #q = 80/16 =># ||||||| (divide by #16# on both sides)
  • #q=5#
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