Question

Question #8e63a

Answer 1

b = `1/18`

Explanation:

I'm going to assume you want to just solve for b here, so:

A "quick" way of doing this is to use the Least Common Multiplier (LCM) of your denominators (9b and 3b)

We can see the LCM of these two numbers is 9

Now we can get to work:

1) Multiply both sides by the LCM (9b)

`color(red)(9b) * (3-2/9b) = (1/3b - 7) * color(red)(9b)`

`27b-2=3-63b`

2) Add 2 to both sides

`color(red)(2+)(27b-2) = (3-63x) color(red)( + 2)`

`27b = -63b + 5`

3) Add 63b to both sides

`color(red)(63b + ) (27b) = (-63b+5) color(red)( + 63b)`

`90b = 5`

4) Divide both sides by 90

`((90x)/color(red)(90)) = (5/color(red)(90))`

`b = 1/18`