How do you evaluate $\frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}$ ?

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Answer 1 · 2017-10-05T08:07:53

$2/((m-3)(m-2)$

Since the denominators in both fractions are the same, we can combine them into one fraction

$(m-1)/(2m^2-10m+12) - (m-5)/(2m^2-10m+12)$

$=((m-1)-(m-5))/(2m^2-10m+12)$

Solving for the numerator

$(m-1-m+5)/(2m^2-10m+12)$

$=4/(2m^2-10m+12)$

Simplify the denominator....

$=4/(2(m-3)(m-2)$

Divide numerator and denominator by 2

$=2/((m-3)(m-2)$

Hope I helped you in this problem!
Cheers!

How do you evaluate \frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}\frac { m - 1} { 2m ^ { 2} - 10m + 12} - \frac { m - 5} { 2m ^ { 2} - 10m + 12}?