How do you graph #y=cos(x/2)#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer sankarankalyanam Oct 5, 2017 #Amplitude =1# & #Period=4pi# #y=cos(x/2)# graph{cos(x/2) [-10, 10, -5, 5]} Explanation: #y=cos(x/2)# #Amplitude a =1# & #Period=(2pi/b)=(2pi)/(1/2)=4pi# Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 8194 views around the world You can reuse this answer Creative Commons License