How do you find w(x+1)w(x+1) given w(x)=x^3-2xw(x)=x32x?

1 Answer
Oct 7, 2017

You just sub in x+1x+1 wherever xx is.

w(x+1)=(x+1)^3-2(x+1)w(x+1)=(x+1)32(x+1)

Explanation:

You have:
w(x)=x^3-2xw(x)=x32x

If you wanted to find w(u)w(u), all you need to do is sub in uu wherever xx is.

So w(u)=u^3-2uw(u)=u32u

Similarly, if you wanted to find w(x+1)w(x+1), you just sub in x+1x+1 wherever xx is.

So w(x+1)=(x+1)^3-2(x+1)w(x+1)=(x+1)32(x+1)

If the question also wants you to then expand and simplify this, you could expand the expression (x+1)^3-2(x+1)(x+1)32(x+1), and then add/subtract common terms.