Question

How do you divide `\frac { n + 9} { n - 3} \div \frac { n + 2} { n }`?

Answer 1

`=(n*(n+9))/(n^2-n-6)`

Explanation:

`((n+9)/(n-3))/((n+2)/n)`
`=(n*(n+9))/((n+2)*(n-3)`
`=(n.(n+9))/(n^2-n-6)`