Question #2a18a

1 Answer
Fty
Oct 7, 2017

#lambda=7.28 xx 10^-11m#

Explanation:

De Brogle's equation is, #lambda = h/(mv)#
Where,

#lambda# is the wavelength, measured in meters
#h# is Planck's constant #=6.63 xx 10^-34J.s#
#m# is the mass of electron #=9.11 xx10^-31k_g#
#v# is the speed, in this case it is #1.0 xx 10^7m.s#

We just need to substitute these numbers into the equation

#=(6.63 xx 10^-34) / ((9.11xx10^-31) xx (1.0xx10^7))#
Then we get, #lambda=7.28 xx 10^-11m#

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