Question #ca344

1 Answer
Oct 8, 2017

#y-5=2(x+2)#

Explanation:

Point slope form is written in the form,
#y-y_1=m(x-x_1)#
Where #y# is your output, #y_1# is a #y#-value on your line, #m# is your slope (given as 2 here), #x# is your input, and #x_1# is #y_1#'s corresponding #x#-value.

In your case, you are given all the things you need to write your equation in point-slope form. Simply plug in your #m# (#2#), your #x_1# (#-2#), and your #y_1# (#5#) which should merit:

#y-5=2(x+2)#

Remember that the #x#-side of the equation is #x-x_1#, so you would really end up with
#"stuff"=2(x--2)#
Which simplifies to
#"stuff"=2(x+2)#