Question

A chord with a length of `1` runs from `pi/3` to `pi/2` radians on a circle. What is the area of the circle?

Answer 1

Area of the circle`=11.7246`

Explanation:

`theta=(pi/2)-(pi/3)=pi/6`
`sin(theta/2)=`(chord/2)/(radius) `=(1/2)/r`
`sin(pi/12)=1/(2r)`
`r=1/(2sin(pi/12))=1.9319`
Area of the circle`=pir^2=pi*(1.9319)^2=11.7246`