How do you solve 2x + 7 \leq 19?

3 Answers
Oct 8, 2017

x <= 6

Explanation:

First, minus the 7 from both sides of the equation and get this:
2x <= 12

Then divide both sides by 2 to get x on itself and get the answer:
x <= 6

Oct 8, 2017

x<=6

Explanation:

2x+7≤19
Subtract 7 from both sides.

2x+7-7≤19-7

2x<=12

(2x)/(2x)<=12/(2x)

x<=6

Oct 8, 2017

x leq 6

Explanation:

To start, pretend theleqsymbol is really and=symbol, and then solve it like a normal algebra equation:

Start with 2x+7leq19.

Replaceleqwith=:

2x+7=19

Subtract 7 from both sides to isolate x:

2x=12

Divide both sides by 2 to get x to be just x, with no coefficients or other terms:

x=6

Replace=withleq:

xleq6

(If you had multiplied or divided by a negative number, you would have had to flip the inequality sign togeq. But you didn't have to, so you're good.)