How do you simplify #(3+5i)(2+4i)#?

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Answer 1 · 2017-10-09T01:09:39

Expand the expression to get:

#22i-14#

To simplify, expand (FOIL) the expression:

#(3+5i)(2+4i)#

#=6+12i+10i+20i^2#

Combining like terms:

#=6+22i+20i^2#

Since #i^2= -1#, we can rewrite that as:

#=6+22i+20(-1)#

#=6+22i-20#

#=22i-14#