How do you factor #7b + 4b ^ { 3}#?

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Answer 1 · 2017-10-09T02:15:34

The answer is #b(7+4b^2)#.

Factor:

#7b + 4b^3#

Factor out the common #b#.

#b(7+4b^2)#

Answer 2 · 2017-10-09T02:18:53

#=>b(b+7/4i)(b-7/4i)#

#(7b+4b^3)#
Taking out b
#=>b(7+4b^2)#
By the factorization of#(7+4b^2)#
#=>b(b+7/4i)(b-7/4i)#
Where #i# is a imaginary number
#i^2=-1#