Looking at #sqrt(4/27)# we can rewrite this as #sqrt4/sqrt27# and immediately notice that the #sqrt4# is #2#. So we can rewrite as #2/sqrt27#
Looking at #sqrt27# is not a perfect square but it can be further simplified if we break up #27# into its factors. So...
#sqrt27=sqrt(9*3)=sqrt9*sqrt3#
We notice that the #sqrt9# is #3# and can rewrite the #sqrt27# as #3sqrt3#. We can't simplify #sqrt3# however as it is not a perfect square so in summary,
#sqrt(4/27)=2/(3sqrt3)#