How do you simplify #\frac { 2} { 2a } + \frac { 4a } { 6a + 12}#?

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Answer 1 · 2017-10-10T19:25:46

#(2a^2+a+2)/(a^2+2a)#

Start by factoring every numerator and denominator:

#2/(2(a))+(2(2a))/(6(a+2))#

Divide away the #2#’s in both fraction:

#cancel(2)/(cancel(2)(a))+(cancel(2)(2a))/(cancel(2)*(3)(a+2))#

So:

#1/a+(2a)/(a+2)#

Get a common denominator of #a^2+2a#

#(a+2)/(a^2+2a)+(2a^2)/(a^2+2a)=(2a^2+a+2)/(a^2+2a)#