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Answer 1 · 2017-10-11T04:37:40

#x^2+y^2-12x-10y+25=0#

The equation of a circle with center #(x_0;y_0)# and radius r is:

#(x-x_0)^2+(y-y_0)^2=r^2#

Then we get the following equation:

#(x-6)^2+(y-5)^2=6^2#

We would transform it to the standard form

#x^2+y^2+ax+by+c=0#:

#x^2-12x+cancel36+y^2-10y+25=cancel36#

#x^2+y^2-12x-10y+25=0#