How do you solve #3n - ( 4n + 2) > 8#?

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Answer 1 · 2017-10-11T08:07:30

#3n-(4n+2)>8=n<-10#

#3n-(4n+2)>8#

Remove the brackets first:

#3n-4n-2>8#

Move the n's to one side of the equation and the numbers to the other (change them from positive to negative or vice-versa when you do so):

#3n-4n>8+2#

#-n>10#

Don't forget to change the sign when you multiply by a negative number:

#n<-10#