How do you find the value of #tan 20(theta)# using the double angle identity?

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Answer 1 · 2017-10-11T11:24:41

Have a look.

For solving this, one should be aware of the formula #rarr#

#tan2theta=(2tantheta)/(1-tan^2theta)#

So, #tan(20theta)#

#=tan(2xx10theta)#

#=(2tan(10theta))/(1-tan^(2)(10theta)#

#=(2tan(2xx5theta))/(1-(tan(2xx5theta))^2)#

In this way continue till you get an expression having only the term #5theta#.

Hope it Helps:)