What is the simplified form of #-3 sqrt32#?

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Answer 1 · 2017-10-11T16:48:49

#2^(-5/3)#

I shall assume you mean #root(-3)32#

#root(-3)32# is equivalent to #32^(-1/3)#

#32^(-1/3)#

#=(2^5)^(-1/3)#

#=2^(-5/3)#

Answer 2 · 2017-10-11T19:22:40

#-12sqrt2#

If the question is:- #-3sqrt32#

#:.=-3sqrt(2*2*2*2*2)#

#sqrt2*sqrt2=2#

#:.=-3*4sqrt2#

#:.=-12sqrt2#