If 94L of a gas at room temperature exerts a pressure of 15kPa on its container, what pressure will the gas exert if the container's volume changes to 73L?

1 Answer
Oct 12, 2017

14.5kPa

Explanation:

Boyle's law states that for an ideal gas P1V, or P=kV where k is a constant.

In this question we are given the pressure and volume, but not the constant, though it is easy to work out.

PV=k

15kPa=1.5104Pa

94L=2.25L=2.25103m3

Therefore, (1.5104)(2.25103)=33.75

Our new volume of 73L gives us the equation of P=33.7573000=101250714,464Pa=14.464kPa14.5kPa