Question

How do you divide `(10x ^ { 3} - 21x ^ { 2} - 6x + 5) \div ( 5x - 3)`?

Answer 1

`2x^2-3x-3-4/(5x-3)`

Explanation:

Use long division:

So:

`(10x^3-21x^2-6x+5)-:(5x-3)=2x^2-3x-3`, `R=-4`

Since the remainder is `-4` we can rewrite that as a fraction:

`2x^2-3x-3-4/(5x-3)`