How do you divide (10x ^ { 3} - 21x ^ { 2} - 6x + 5) \div ( 5x - 3)?

1 Answer
Oct 12, 2017

2x^2-3x-3-4/(5x-3)

Explanation:

Use long division:

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So:

(10x^3-21x^2-6x+5)-:(5x-3)=2x^2-3x-3, R=-4

Since the remainder is -4 we can rewrite that as a fraction:

2x^2-3x-3-4/(5x-3)