How do you graph F(x)=log_3(x-2)?
1 Answer
Oct 13, 2017
Explanation:
x-2=0
x=2
So, the vertical asymptote is2
at
x=3
log_3(3-2)=log_3(1)=0->(3,0) at
x=5
log_3(5-2)=log_3(3)=1->(5,1) at
x=11
log_3(11-2)=log_3(9)=2->(11,2)