How do you solve #\frac { 2 k + 5} { 5} + 9= - ( k - 3)#?

2 Answers
Oct 14, 2017

#k=-5#

Refer to the explanation for the process.

Explanation:

Solve:

#(2k+5)/5+9=-(k-3)#

Expand the right side.

#(2k+5)/5+9=-k+3#

Subtract #9# from both sides.

#(2k+5)/5=-k+3-9#

Simplify.

#(2k+5)/5=-k-6#

Multiply both sides by #5#.

#2k+5=5(-k-6)#

Simplify.

#2k+5=-5k-30#

Subtract #5# from both sides.

#2k=-5k-30-5#

Simplify.

#2k=-5k-35#

Add #5k# to both sides.

#2k+5k=-35#

Simplify.

#7k=-35#

Divide both sides by #7#.j

#k=-35/7#

Simplify.

#k=-5#

Oct 14, 2017

#k=#-5

Explanation:

Taking L C M and removing bracket in R H S,
#(2k+5+45)/5=-k+3#

#2k+50=-5k+15# Cross multiplying and simplifying LHS,

#2k+5k=-50+15# Bringing k terms to LHS and constants to RHS.

#7k=-35#

#k=(-35)/7=#-5