What are the #x# intercepts of the function #f(x)=-2x^2-3x+20#?

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Answer 1 · 2017-10-14T21:05:39

#(5/2,0) and (-4,0)#

#f(x)=-2x^2-3x+20#

in order to find the #x# intercepts, #f(x)# must equate to #0#

#=>0=-2x^2-3x+20#

#=>2x^2+3x-20=0#

#=>(2x-5)(x+4)=0#

Using the zero product property: if #(a)*(b)=0# then #a and b# each equate to 0

#=>2x-5=0 and x+4 = 0#

#=>x=5/2 and -4#

#=># the x intercepts are #(5/2,0) and (-4,0)#