Question #050ad

1 Answer
Oct 15, 2017

I'll assume #3(1-2x)# is in the denominator.

To find an inverse, first make the expression an equation. For this, simply define a variable #y# as:

#y=1/(3(1-2x))#

Now, switch every #x# to a #y# and every #y# to a #x#.

#x=1/(3(1-2y))#

Finally, solve for #y#.

#3x=1/(1-2y)#

#1/(3x)=1-2y#

#1/(3x)-1=-2y#

#y=1/2-1/(6x)#

#y=(3x-1)/(6x)#