If $f (x) = x^{\frac{1}{2}} - x$ $f(x)=x^(1/2)-x$ and $g (x) = 2 x^{3} - x^{\frac{1}{2}} - x$ $g(x)=2x^3-x^(1/2)-x$ , how do you find $f (x) - g (x)$ $f(x)-g(x)$ ?

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If $f (x) = x^{\frac{1}{2}} - x$ $f(x)=x^(1/2)-x$ and $g (x) = 2 x^{3} - x^{\frac{1}{2}} - x$ $g(x)=2x^3-x^(1/2)-x$ , how do you find $f (x) - g (x)$ $f(x)-g(x)$ ?

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Answer 1 · 2017-10-16T01:05:51

$f (x) - g (x) = 2 x^{\frac{1}{2}} - 2 x^{3}$ $f(x) - g(x) = 2x^(1/2) - 2x^3$

Explanation:

Just do the arithmetic:

$f (x) - g (x) = x^{\frac{1}{2}} - x - (2 x^{3} - x^{\frac{1}{2}} - x)$ $f(x) - g(x) = x^(1/2) - x - (2x^3 - x^(1/2) - x)$

$f (x) - g (x) = x^{\frac{1}{2}} - x - 2 x^{3} + x^{\frac{1}{2}} + x$ $f(x) - g(x) = x^(1/2)- x - 2x^3 + x^(1/2) + x$

$f (x) - g (x) = 2 x^{\frac{1}{2}} - 2 x^{3}$ $f(x) - g(x) = 2x^(1/2) - 2x^3$

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If $f (x) = x^{\frac{1}{2}} - x$ $f(x)=x^(1/2)-x$ and $g (x) = 2 x^{3} - x^{\frac{1}{2}} - x$ $g(x)=2x^3-x^(1/2)-x$ , how do you find $f (x) - g (x)$ $f(x)-g(x)$ ?

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Explanation:

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If f(x)=x12−xf(x)=x^(1/2)-x and g(x)=2x3−x12−xg(x)=2x^3-x^(1/2)-x, how do you find f(x)−g(x)f(x)-g(x)?

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If $f (x) = x^{\frac{1}{2}} - x$ $f(x)=x^(1/2)-x$ and $g (x) = 2 x^{3} - x^{\frac{1}{2}} - x$ $g(x)=2x^3-x^(1/2)-x$ , how do you find $f (x) - g (x)$ $f(x)-g(x)$ ?