Question

What is the equation of the line that passes through (-6, -8) and (-7, y) and has a slope of -8?

Answer 1

From here we just use the point (-6,-8) and slope -8 to write the equation.

Explanation:

The equation of line:
y=mx+c
we have y=-8 x=-6 and m=-8 , so we need to find c.
`-8=-8*-6+c`
`-8=48+c`
`c=-56`
Equation is y=-8x-56

if you would like to know how to find y in point (-7,y) the solution is below, but you don't need it for this question.

The slope or gradient has this formula when two points are given:
`m=(y1-y)/(x1-x)`

In this case we have the points (-6,-8) and (-7,y) and m=-8.
We use the formula:

`-8=(-8-y)/(-6-(-7))`
`-8=(-8-y)/1`
`-8+8=-y`

`y=0`