How do you evaluate #(- 6- - 6) ^ { 3} + 4#?

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Answer 1 · 2017-10-17T01:02:17

#4#

Focus on the parenthesis first. We have

#-6--6# which is simplified to #-6+6# which is just #0#

So our expression is now

#(0)^3+4#

We now evaluate

#0^3+4#

#=0+4#

#=4#

Answer 2 · 2017-10-17T01:03:05

The answer is #4#.

Begin by simplifying within the parentheses.

#(-6-(-6))^3+4 = 0^3+4# because #-6-(-6)=-6+6=0#

#0^3=0#, so #0^3+4 = 4#

The answer is #4#.