Question #d8ac3
2 Answers
See the answer below...
Explanation:
#(1+cosA)(1+cosB)(1+cosC)=(1-cosA)(1-cosB)(1-cosC)=k# [Assume it]Now we can write that
#k^2={(1+cosA)(1+cosB)(1+cosC)}{(1-cosA)(1-cosB)(1-cosC)}#
#=>k^2=(1-cos^2A)(1-cos^2B)(1-cos^2C)#
#=>k^2=sin^2A.sin^2B.sin^2C#
#=>k=+-sinAsinBsinC# As we assumed before
#(1+cosA)(1+cosB)(1+cosC)=k=+-sinAsinBsinC#
PROVEDHope it helps...
Thank you
Please refer to a Proof in the Explanation.
Explanation:
We will use the following Identities :
Given that,
Now,
Similarly,
Hence, the Proof.