Question

Question #5c5a5

Answer 1

a) `Phi_B=0.0306` Wb
b) `Phi_B=0.0184` Wb

Explanation:

Magnetic flux is calculated as `Phi_B = B*A*costheta`
where `theta` is the angle between the direction of the field and the normal to the surface enclosed by the loop.

In this case, the field is 0.230 T, and the area is `A=pi*r^2= 0.0133 m^2`

(Note the necessary change from cm to m.)

So, if `theta` = 0°, as in part a of your question (If the circle lies in the `x-y` plane, the normal points perpendicular to the plane - in the direction of the z-axis.)

`Phi_B= (0.230*0.0133)*cos(0°)=0.00306` Wb (webers)

And in part b, where `theta`= 53.1°

`Phi_B= (0.230*0.0133)*cos(53.1°)=0.00184` Wb