How do you graph #y+4=0#?
2 Answers
See a solution process below:
Explanation:
We can solve this for
This equation shows for each and every value of
We can find two points to plot as:
For
For
graph{(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}
We can now draw a line through the two points giving:
graph{(y+4)(x^2+(y+4)^2-0.075)((x-5)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}
We can this is a horizontal line from
Refer to the explanation.
Explanation:
Graph:
Solve for
The graph will be a horizontal line at