How to rationalize the denominator here, #4/(sqrt7 - 2# ?

1 Answer
Oct 18, 2017

#4/3(sqrt7+2)#

Explanation:

#4/(sqrt7-2)#.To rationalize we should multiply both denominator

and numerator by the conjugate of denominator to get rid of

roots from the denominator by achieving #a^2-b^2# form.

# =(4*(sqrt7+2))/((sqrt7-2)(sqrt7+2)) #

#(4*(sqrt7+2))/(7-4) = (4*(sqrt7+2))/3 #

#4/3(sqrt7+2)# [Ans]