Given #f(x) = (2x-1)/(x-1) # how do you find f^-1(x)?

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Answer 1 · 2017-10-18T18:54:51

#x= (-(1+y))/(y-2)#

#f(x) = (2x-1)/(x+1)#

#y = (2x-1)/(x+1)#

#y(x+1)=2x-1#

#yx+y=2x-1#

subtract #2x#:
#(yx-2x)+y=-1#
#x(y-2)+y=-1#

subtract #y#:

#x(y-2)=-1 -y#

divide by #(y-2)#:

#x=(-1-y)/(y-2)#

#x= (-(1+y))/(y-2)#