How do I find all the solutions for cos(x)tan(x)=tan(x) on one interval rotation of the unit circle?

1 Answer
Oct 19, 2017

In [0, 2pi), we have x in 0 and pi

Explanation:

We can immediately rewrite as

0 = tanx - cosxtanx

0 = tanx(1 - cosx)

So we now have two equations.

tanx = 0

x = 0 or pi

AND

1 - cosx= 0

x = 0

So in the interval [0, 2pi), the solutions will be x in 0 uu pi

Hopefully this helps!