How to determine the x and y intercepts of x-7y=7?

1 Answer
Oct 20, 2017

x-intercept = (7,0)
y-intercept = (0,-1)

Explanation:

Firstly, rearrange the equation into the simple form of a linear function, which is #y=bx+c#

So, #-7y=7-x# , then divide both sides by (-7) to isolate "y" on its own. Therefore,

#y=1/7x-1#, and this is your simplified linear function in the form #y=bx+c#

Now for the easy part, determining your x and y intercepts.

y-int is when x=0, thus #y=0-1# by substituting it into the linear equation. So, the y-intercept is (0,-1)

x-int is when y=0, thus #0=1/7x-1# by substitution. So, the x-intercept is (7,0).

Hope this helped :)